A new youth sports center is being built in pagosa springs. The permitted of the rectangular playing field is 524 yards. The length of the field is 8 yards lass then quadruple the with. What are the dimensions of the playing field?

Answer:Length = 208 yards Width = 54 yardsStep-by-step explanation:Let the length of the field be "x" yards and the width be "y" yards. Its given that the length is 8 less than quadruple(4 times) the width. So x is 8 less than 4y. We can write this in equation as:x = 4y - 8                               Equation 1Perimeter of the field is given to be 524 yards. Since, the field is rectangular, its perimeter is calculated as:Perimeter = 2 (Length + Width)Using the values, we get:2(x + y) = 524                         Equation 2Substituting the value of x from Equation 1 into Equation 2, we get:2(4y - 8 + y) = 5242(5y - 8) = 5245y - 8 = 524/25y - 8 = 2625y = 262 + 8 5y = 270y = 54 yardsSubstituting the value of y in Equation 1, we get:x = 4y - 8 = 4(54) - 8 = 208 yardsThus, the length of the playing field is 208 yards and its width is 54 yards.