A red die is tossed and then a green die is tossed. What is the probability that the red die shows an even number or the green die shows an even number?

Using it's concept, it is found that there is a [tex]\frac{3}{4}[/tex] probability that the red die shows an even number or the green die shows an even number.What is a probability?A probability is given by the number of desired outcomes divided by the number of total outcomes.A die has six sides, of which three are even and three are odd, hence:P(A) = 3/6 = 1/2.P(B) = 3/6 = 1.2.P(A and B) = P(A)*P(B) = 1/4.The "or probability" is given by:[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]Hence:[tex]P(A \cup B) = \frac{1}{2} + \frac{1}{2} - \frac{1}{4} = \frac{3}{4}[/tex]More can be learned about probabilities at