Given f(x)=17-x^2 what is the average rate of change in f(x) over the interval [1, 5]?-6-1/21/41
Accepted Solution
A:
Answer: choice A) -6
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Work Shown:
Plug in x = 1 f(x) = 17-x^2 f(1) = 17-1^2 f(1) = 17-1 f(1) = 16
Then plug in x = 5 f(x) = 17-x^2 f(5) = 17-5^2 f(5) = 17-25 f(5) = -8
So the average rate of change (AROC) from x = 1 to x = 5 is... AROC = (f(b)-f(a))/(b-a) AROC = (f(5)-f(1))/(5-1) AROC = (-8-16)/(5-1) AROC = (-24)/(4) AROC = -6